Minor structural changes
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@ -7,6 +7,8 @@
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\usepackage{float}
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\usepackage{float}
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\raggedbottom
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\raggedbottom
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\usepackage{enumitem}
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% Where are our images?
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% Where are our images?
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\graphicspath{{images/}}
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\graphicspath{{images/}}
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@ -63,9 +65,20 @@ It also provides several worked equations to serve as examples.
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\section{Quadratic Equations}
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\section{Quadratic Equations}
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\textbf{Quadratic equations} are equations of the form $ax^2+bx+c=0$.
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\textbf{Quadratic equations} are equations of the form $ax^2+bx+c=0$, or that can be written in that form.
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The simplest quadratic equation to solve is the type where both sides are a perfect square, because you can solve them by taking the square root of both sides:
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When we say ``of the form'' what we mean is
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\begin{itemize}[noitemsep]
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\item The letters $a, ~b,$ and $c$ represent constants, and that both $b$ and $c$ can be zero.
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\item There is one term that contains the variable $x^2$
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\end{itemize}
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For example, the equation $3x^2+2x=5$ is a quadratic equation because it is written in the form $ax^2+bx+c=0$.
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However, the equation $5=2-3x^2$ is also a quadratic equation because it can be rewritten as $3x^2+3=0$. In this case, the value for $b$ is zero. (This could also be written as $3x^2+0x+3=0$.)
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\paragraph{Perfect Square Quadratic Equations} The simplest quadratic equation to solve is the type where both sides are a perfect square, because you can solve them by taking the square root of both sides:
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\begin{align}\label{eq1}
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\begin{align}\label{eq1}
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\begin{split}
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\begin{split}
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@ -80,7 +93,7 @@ x &= \pm3
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\paragraph{Note:} Because we are taking the square root of a constant, we must include both the positive and negative values of the square root as the solution, hence $\pm3$. Substituting either $3$ or $-3$ into $x$ in the original equation results in a value of 36. (In story problems, the situation may mean that we can safely ignore one of these values.)
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\paragraph{Note:} Because we are taking the square root of a constant, we must include both the positive and negative values of the square root as the solution, hence $\pm3$. Substituting either $3$ or $-3$ into $x$ in the original equation results in a value of 36. (In story problems, the situation may mean that we can safely ignore one of these values.)
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\paragraph{Factorable equations} The other type of quadratic equation is one that can easily be solved by factoring. For example,
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\paragraph{Factorable Quadratic Equations} The other type of quadratic equation is one that can easily be solved by factoring. For example,
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\begin{align}\label{eq2}
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\begin{align}\label{eq2}
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\begin{split}
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\begin{split}
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@ -156,7 +169,7 @@ and then solve for $x$ (step six): \[x=\pm\sqrt{3} -2\]
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Conventionally, we would write this as $x=-2+\sqrt{3}, -2-\sqrt{3}$.
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Conventionally, we would write this as $x=-2+\sqrt{3}, -2-\sqrt{3}$.
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\krule{6pt}{6pt}
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\newpage
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\noindent{}Here is the entire sequence all together:
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\noindent{}Here is the entire sequence all together:
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@ -176,18 +189,27 @@ x &= -2\pm\sqrt{3} && && &&\text{Step 6}
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\hrule
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\hrule
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\section{Example \#2}
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\subsection{Example \#2}
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For our second example, we will look at an equation where $a$ is not equal to 1.
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For our second example, we will look at an equation where $a$ is not equal to 1.
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\section{Example \#3}
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\subsection{Example \#3}
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For our third example, we will look at an equation where the right side is not a perfect square.
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For our third example, we will look at an equation where the right side is not a perfect square.
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\section{Example \#4}
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\subsection{Example \#4}
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For our fourth example, we will look at an equation where neither $a$ is equal to 1 nor the right side is a perfect square.
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For our fourth example, we will look at an equation where neither $a$ is equal to 1 nor the right side is a perfect square.
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\pagestyle{lastpage}% Remove the header from the last page; comment this out if the document ends on an odd-numbered page
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\section{More Worked Examples}
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\subsection{Example \#5.1}
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\subsection{Example \#5.2}
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\section{An Explanation of the Quadratic Equation}
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%\pagestyle{lastpage}
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% Remove the header from the last page; comment this out if the document ends on an odd-numbered page
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\end{document}
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\end{document}
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